The analyzer has detected a potential error, related to a strange usage of operators ('=!', '=-', '=+'). Most likely, their usage is incorrect and one of the following operators should be used here: '!=', '-=', '+='.
Operator '=!'
Example of suspicious code:
boolean a = ... ; boolean b = ... ; ... if (a =! b) { ... }
It's most probably that this code should check that the 'a' variable is not equal to 'b'. If so, the correct code should look like follows:
if (a != b) { ... }
The analyzer accounts for formatting in the expression. That's why if it is exactly assignment you need to perform - not comparison - you should specify it through parentheses or blanks. The following code samples are considered correct:
if (a = !b) ... if (a=(!b)) ...
Operator '=-'
Example of suspicious code:
int size = ... ; int delta ... ; ... size =- delta;
This code may be correct, but it is highly probable that there is a misprint and the programmer actually intended to use the '-=' operator. This is the fixed code:
size -= delta;
If the code is correct, you may type in an additional space between the characters '=' and '-' to remove the V6015 warning. This is an example of correct code where the warning is not generated:
size = -delta;
Operator '=+'
Example of suspicious code:
int size = ... ; int delta ... ; ... size =+ delta;
This is the fixed code:
size+=delta;
If this code is correct, you may remove '+' or type in an additional space to prevent showing the V6015 warning. The following is an example of correct code where the warning is not generated:
size = delta; size = +delta;
This diagnostic is classified as: